Ham Amateur Radio Technician 2026 – 400 Free Practice Questions to Pass the Exam

To determine the output power based on the given voltage across the load, it's important to use the relationship between voltage, current, and resistance. In this case, when voltage is specified as peak-to-peak (500 volts), it is necessary to convert this voltage for calculations involving power, which is usually expressed in terms of root mean square (RMS) voltage for AC circuits.

The peak voltage can be calculated from the peak-to-peak voltage by dividing it by 2, giving us 250 volts peak. The corresponding RMS value for a sinusoidal voltage is derived from peak voltage using the formula:

RMS voltage = Peak voltage / √2 = 250 V / √2 ≈ 176.78 V.

Now, to calculate output power, additional context regarding the load impedance (resistance, R) is assumed. Power can be calculated using the formula:

Power (P) = V(RMS)² / R.

Assuming a standard resistive load (such as 100 ohms), the output power would be:

P = (176.78 V)² / 100 Ohms ≈ 312.13 watts.

However, the exact output power can also vary based on different assumed impedance values, which can